Solve the following

Question:

Express $\frac{-3}{5}$ as a rational number with denominator

(i) 20

(ii) −30

(iii) 35

(iv) −40

Solution:

If $\frac{a}{b}$ is a fraction and $m$ is a non-zero integer, then $\frac{a}{b}=\frac{a \times m}{b \times m}$.

Now,

(i) $\frac{-3}{5}=\frac{-3 \times 4}{5 \times 4}=\frac{-12}{20}$

(ii) $\frac{-3}{5}=\frac{-3 \times-6}{5 \times-6}=\frac{18}{-30}$

(iii) $\frac{-3}{5}=\frac{-3 \times 7}{5 \times 7}=\frac{-21}{35}$

(iv) $\frac{-3}{5}=\frac{-3 \times-8}{5 \times-8}=\frac{24}{-40}$

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