Solve the following

Question:

Factorise:
m2 − 4mn + 4n2

Solution:

We have:

$m^{2}-4 m n+4 n^{2}=m^{2}-2 \times m \times 2 n+(2 n)^{2}$

$=(m-2 n)^{2}$

$\therefore m^{2}-4 m n+4 n^{2}=(m-2 n)^{2}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now