Question:
Square of $\left(\frac{-2}{3}\right)$ is
(a) $-\frac{2}{3}$
(b) $\frac{2}{3}$
(c) $-\frac{4}{9}$
(d) $\frac{4}{9}$
Solution:
(d) 4/9
To square a number is to raise it to the power of 2. Hence, the square of (−2/3) is
$\frac{(-2)^{2}}{3^{2}}=\frac{4}{9} \quad \cdots\left((a / b)^{n}=\left(a^{n}\right) /\left(b^{n}\right)\right)$
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