The area of the circle that can be

(d) Given, side of square $=6 \mathrm{~cm}$

$\therefore$ Diameter of a circle, $(d)=$ Side of square $=6 \mathrm{~cm}$

$\therefore \quad$ Radius of a circle $(r)=\frac{d}{2}=\frac{6}{2}=3 \mathrm{~cm}$

$\therefore \quad$ Area of circle $=\pi(r)^{2}$

$=\pi(3)^{2}=9 \pi \mathrm{cm}^{2}$