The probability of getting 2 heads, when two coins are tossed, is

Question:

The probability of getting 2 heads, when two coins are tossed, is

(a) 1

(b) $\frac{3}{4}$

(c) $\frac{1}{2}$

(d) $\frac{1}{4}$

 

 

 

Solution:

All possible outcomes are HH, HT, TH and TT.

​Total number of outcomes = 4.

Getting 2 heads means getting HH.

Numbers of favourable outcomes = 1

$\therefore \mathrm{P}($ getting 2 heads $)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$

$=\frac{1}{4}$

Thus, the probability of getting 2 heads is $\frac{1}{4}$.

Hence, the correct answer is option (d).

 

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