Question:
The volume of a cube is 729 cm3. Find its surface area.
Solution:
Let the edge of the cube be $a$.
As,
Volume of the cube $=729 \mathrm{~cm}^{3}$
$\Rightarrow a^{3}=729$
$\Rightarrow a=\sqrt[3]{729}$
$\Rightarrow a=9 \mathrm{~cm}$
Now,
Surface area of the cube $=6 a^{2}$
$=6 \times 9 \times 9$
$=486 \mathrm{~cm}^{2}$
So, the surface area of the cube is 486 cm2.
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