Question:
Tick (✓) the correct answer
The value of $(-2)^{-5}$ is
(a) $-32$
(b) $\frac{-1}{32}$
(c) 32
(d) $\frac{1}{32}$
Solution:
(b) $\frac{-1}{32}$
$(-2)^{-5}=\frac{1}{(-2)^{5}}=\frac{1}{-32}=\frac{1 \times(-1)}{-32 \times(-1)}=\frac{-1}{32}$
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