Question:
Tick (✓) the correct answer
The sum of two rational numbers is $-3$. If one of them is $\frac{-10}{3}$ then the other one is
(a) $\frac{-13}{3}$
(b) $\frac{-19}{3}$
(c) $\frac{1}{3}$
(d) $\frac{13}{3}$
Solution:
(C) $\frac{1}{3}$
Let the other number be x.
Now,
$x+\left(-\frac{10}{3}\right)=-3$
$\Rightarrow x=-3+\left(\right.$ Additive inverse of $\left.-\frac{10}{3}\right)$
$\Rightarrow x=\left(-3+\frac{10}{3}\right)$
$=\frac{-3}{1}+\frac{10}{3}$
$=\frac{(-9+10)}{3}$
$=\frac{1}{3}$
Thus, the other number is $\frac{1}{3}$
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