Question:
To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn, so that ∠BAX is an acute angle and then at equal distances points are marked on
the ray AX such that the minimum number of these points is
(a) 8
(b) 10
(c) 11
(d) 12
Solution:
(d) We know that, to divide a line segment AB in the ratio m: n, first draw a ray AX which makes an acute angle ∠BAX, then marked m + n points at
equal distance.
Here, m = 5, n = 7
So, minimum number of these points = m+n = 5 + 7 = 12.
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