What will be the height of a cuboid of volume 168 m

Volume of the cuboid $=168 \mathrm{~m}^{3}$

Area of its base $=28 \mathrm{~m}^{2}$

Let $h \mathrm{~m}$ be the height of the cuboid.

Now, we have the following:

Area of the rectangular base $=$ lenght $\times$ breadth

Volume of the cuboid $=$ lenght $\times$ breadth $\times$ height

$\Rightarrow$ Volume of the cuboid $=($ area of the base $) \times$ height

$\Rightarrow 168=28 \times h$

$\Rightarrow h=\frac{168}{28}=6 \mathrm{~m}$

$\therefore$ The height of the cuboid is $6 \mathrm{~m}$.